[APBeta] Script error

Paul Rodman paul at ilanga.com
Mon Aug 31 11:33:59 PDT 2009


On Aug 31, 2009, at 10:55 AM, Jeff Young wrote:

> The 3-state does seem optimal, and I'd expect it's not much more  
> work on your side.

Nope. Already done.

Paul R.

>
>> -----Original Message-----
>> From: apbeta-bounces at lists.astroplanner.net [mailto:apbeta-bounces at lists.astroplanner.net 
>> ] On Behalf Of
>> Paul Rodman
>> Sent: Monday, August 31, 2009 6:45 PM
>> To: AstroPlanner Beta Testers
>> Subject: Re: [APBeta] Script error
>>
>>
>> On Aug 31, 2009, at 10:01 AM, Jeff Young wrote:
>>
>>> Hmmm... your comment leads me to believe I misunderstood.  I thought
>>> SiteResource.All(true) would return only active ones, and
>>> SiteResource.All(false) would return both active and inactive.  Was
>>> SiteResource.All(false) supposed to return only inactive?  (I don't
>>> think that would be terribly useful.)
>>
>> My thinking was (and it was a toss-up):
>>
>> If you have a list of active resources and a list of inactive
>> resources, it's easy enough to concatenate them.
>>
>> OTOH, if you have a list of active and a list of active+inactive,  
>> then
>> to tell them apart you have to look at the Active property.
>>
>> However, for the reasons you wanted this in the first place, I'm
>> guessing that Plan B is slightly less hassle (i.e. no concatenating  
>> or
>> searching two separate lists).
>>
>> There is a third option I contemplated, and will probably use, and
>> that's to have an integer rather than boolean parameter: active_only,
>> inactive_only, or active_and_inactive
>>
>> Paul R.
>>
>>>> -----Original Message-----
>>>> From: apbeta-bounces at lists.astroplanner.net [mailto:apbeta-bounces at lists.astroplanner.net
>>>> ] On Behalf Of
>>>> Paul Rodman
>>>> Sent: Monday, August 31, 2009 5:55 PM
>>>> To: AstroPlanner Beta Testers
>>>> Subject: Re: [APBeta] Script error
>>>>
>>>> At least here, SiteResource.All is returning an empty array,
>>>> SiteResource.All(false) is returning all site resources (rather  
>>>> than
>>>> just the inactive ones).




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